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[원서] Proakis J. - Solutions for Digital communications, 4ed

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작성일 19-12-19 16:57

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Download : Proakis J Solutions for Digital communications 4ed.pdf




[원서] Proakis J. - Solutions for Digital communications, 4ed

솔루션,기타,솔루션
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Download : Proakis J Solutions for Digital communications 4ed.pdf( 15 )



Proakis%20J%20%20Solutions%20for%20Digital%20communications%204ed_pdf_01.gif Proakis%20J%20%20Solutions%20for%20Digital%20communications%204ed_pdf_02.gif Proakis%20J%20%20Solutions%20for%20Digital%20communications%204ed_pdf_03.gif Proakis%20J%20%20Solutions%20for%20Digital%20communications%204ed_pdf_04.gif Proakis%20J%20%20Solutions%20for%20Digital%20communications%204ed_pdf_05.gif Proakis%20J%20%20Solutions%20for%20Digital%20communications%204ed_pdf_06.gif



癤 Corrections to Digital Communications, 4th Edition
1. Page 31, Equation (2.1-54)
First line: yl instead of y2 Second line: gn instead of g1

2. Page 163, Equation (4.2-30)

should be: s(t) = ao/2 + 誇
k=1
3. Page 163, Equation (4.2-31)
T
should be: ak = (2/T) s(t) cos 2kt/T dt , k`0 0
T
bk = (2/T) s(t) sin 2kt/T dt , k`1 0

4. Page 178, 7 lines from the top

should be: sqrt (2琯) instead of 琯 sqrt (2)

5. Page 238, Equation (5.1-19)

should be: h(T- ) ins

癤 Corrections to Digital Communications, 4th Edition
1. Page 31, Equation (2.1-54)
First line: yl instead of y2 Second line: gn instead of g1

2. Page 163, Equation (4.2-30)

should be: s(t) = ao/2 + 誇
k=1
3. Page 163, Equation (4.2-31)
T
should be: ak = (2/T) s(t) cos 2kt/T dt , k`0 0
T
bk = (2/T) s(t) sin 2kt/T dt , k`1…(생략(省略))
[원서] Proakis J. - Solutions for Digital communications, 4ed , [원서] Proakis J. - Solutions for Digital communications, 4ed기타솔루션 , 솔루션


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